Cannot be declared with constexpr specifier
http://m.genban.org/ask/c/39869.html WebOtherwise, or if a constexpr specifier is used in a reference declaration, every full expression that appears in its initializer shall be a constant expression.[...] 即使使用 -std=c++14 -pedantic 或 -std=c++11 -pedantic 也不会产生警告 ... While clang does not allow the code with any combination of flags I have tried.
Cannot be declared with constexpr specifier
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WebThe constexpr specifier shall be used for values that can be determined at compile time. Not Compliant : ... or enumeration shall not be declared in the definition of its type. Compliant : A7-2-1: An expression with enum underlying type shall only have values corresponding to the enumerators of the enumeration. WebMay 21, 2024 · A constexpr specifier used in an object declaration declares the object as const. Such an object shall have literal type and shall be initialized. In any constexpr variable declaration, the full-expression of the initialization shall …
WebJan 13, 2024 · decomposition declaration cannot be declared 'constexpr' Dropping the constexpr definition and changing to a regular assert () works on both compilers. None of the WG21 papers on this feature mention the constexpr keyword, neither in … WebOct 13, 2024 · Somewhat relevant in the context of the latter is that a constexpr static data member declaration with initialization is, also, as of C++17, a definition, allowing for the specification that constexpr shall only be applied to the variable definition (i.e., never to a non-initializing declaration). See [depr.static_constexpr]/1.
WebThe constexpr!specifier shall be applied only to the definition of a function or function template. A function or static data member declared with the constexpr or constexpr! specifier is implicitly an inline function or variable (10.1.6). If any declaration of a function or function template has a constexpr or constexpr! specifier, then all ... WebJun 3, 2014 · 7.1.6.4p auto specifier ... A static data member of literal type can be declared in the class definition with the constexpr specifier; if so, its declaration shall specify a brace-or-equal-initializer in which every initializer-clause that is an assignment-expression is a constant expression. ...
WebFeb 21, 2024 · A reference may be declared as constexpr when both these conditions are met: The referenced object is initialized by a constant expression, and any implicit conversions invoked during initialization are also constant expressions. All declarations of a constexpr variable or function must have the constexpr specifier. constexpr float x = …
WebIf the member is declared with the constexpr specifier, it may be redeclared in namespace scope with no initializer (this usage is deprecated; see D.1). This comes with the same machinery that introduced the non- constexpr version of … daughter of jeb bushWebA call to a constexpr function produces the same result as a call to an equivalent non-constexpr function in all respects, except that a call to a constexpr function can appear in a constant expression. A constexpr function is implicitly inline. The main function cannot be declared with the constexpr specifier. bk root beer stands shredded chicken recipeWebMar 28, 2024 · The central problem is that class members are generally not considered to be declared until after the class in which they're declared is complete. Thus, regardless … daughter of jephthahWebJan 15, 2024 · gcc 4.8.3 (cygwin x64) with -std=c++11 does not recognize the use of a constexpr parameter. Is that standard? I am not experienced with C++ 14 but is it … bkrstll glbl precious mtl deWebThe main function cannot be declared with the constexpr specifier. Parent topic: Functions. Related reference. The constexpr specifier (C++11) Generalized constant … bkr silicone glass water bottleWebApr 24, 2015 · A static data member of literal type can be declared in the class definition with the constexpr specifier; if so, its declaration shall specify a brace-or-equal-initializer in which every initializer-clause that is an assignment-expression is a constant expression. [ Note: In both these cases, the member may appear in constant expressions ... daughter of jennifer lopezWebThe constexpr specifier shall be applied only to the definition of a variable, the declaration of a function or function template, or the declaration of a static data member of a literal type. A lambda expression is none of those things and thus may not be declared constexpr. Share Improve this answer Follow answered Jun 21, 2011 at 3:48 bkr software holding